Exercise 8
Question 1.
- Show that the minimax estimator for the probability of success p
from Y ~ B(n,p)
w.r.t. the quadratic loss L(p,a)=(p-a)2 is
(y+n1/2/2)/(n+n1/2).
- (hint: consider the Beta family of priors on p
and show that for a specific choice
of α and β this estimator is a Bayes rule whose risk does not depend on
p).
- Is the above estimator admissible?
- Whether a "usual" (MLE, UMVUE, etc.) estimator Y/n is admissible w.r.t the
quadratic loss?
- (hint: use the fact that X/n is a Bayes rule w.r.t. to the loss function
L1(p,a)=(p-a)2/(p(1-p)))
Question 2.
Assume we want to test two simple hypotheses H0: θ=θ0 vs.
H1: θ=θ1 based on a random sample
y1,...,yn ~ f(y|θ), where the prior probabilities of the
hypotheses are p0 and p1=1-p0 respectively.
The loss is L0 for erroneous
acception of H0, L1 for erroneous acception of
H1 and zero for a correct decision ("0-Li" loss).
- Derive the resulting Bayes testing rule.
- Interpretate the Bayes rule from the previous paragraph in terms of the
frequentist approach. Is it a most powerful test? What is the critical value
for the test statistic?
- Let α and β be the probabilites of the I and II Type Errors
respectively for the above test. Show that if L1α = L0β,
then it is also a minimax test.
- Let y1,...,y100 be a random sample from a
N(μ,25) distribution. Obtain the minimax test for testing
H0: μ=0 vs.
H1: μ=2 under "0-Li" loss, where L0=10 and
L1=25.
Question 3.
A device has been created to classify type of blood: A, B, AB or O. The device
measures a certain quantity X, which has a density
f(x|θ)=e-(x-θ), x > θ.
If 0 < θ < 1, the blood is of type AB; if
1 < θ < 2, the blood is of type A; if 2 < θ < 3, the blood is of type B; and if
θ > 3, the blood is of type O. It is known that in the population as a whole,
p(θ) ~ exp(1).
The loss in misclassifying the blood is given in the following table:
Classified As
| | | | AB | A | B | O
|
| True | | AB | 0 | 1 | 1 | 2
|
| Blood | | A | 1 | 0 | 2 | 2
|
| Type | | B | 1 | 2 | 0 | 2
|
| | | O | 3 | 3 | 3 | 0
|
A patient has been tested and x=4 is observed. What is the Bayes action?
Question 4.
Children are given an intelligence test. The test result X is
N(μ,100), where μ is the true IQ (intelligence) level of child.
It is known that in the population as a whole, μ is distributed
N(100,225). A young Genius got 115 in the test.
- Find the Bayes estimate for the Genius' IQ w.r.t. the quadratic loss
L(μ,a)=(μ-a)2.
- In estimating IQ, it is deemed to be twice harmful to underestimate as to
overestimate and the following loss is felt appropriate: L(μ,a)=2(μ-a),
μ ≥ a and (a-μ), μ < a.
Find the Bayes estimate for the Genius' IQ w.r.t. this loss.
- Some people say that it is important to detect particularly high or low
IQs and use the weighted quadratic loss
L(μ,a)=(μ-a)2exp{(μ-100)2/900} (note that this
means that detecting an IQ of 145 or 55 is about nine times as important as
detecting an IQ of 100). Find the Bayes
estimate for Genius' IQ.
- Genius is to be classified as having below average IQ (less than 90),
average (90 to 110), or above average IQ (over 110). Find the corresponding
Bayes action and classify Genius to one of these three groups.