Exercise 8

 

 

 

1.The following data, which are given in coded units, were obtained from a tool-life testing investigation in which X1 = measure of the feed, X2 = measure of the speed,

Y = measure of the tool life:

 

 

X1

X2

Y

-1

-1

61

1

-1

42

-1

1

58

1

1

38

0

0

50

0

0

51

 

 

(a)Obtain the least squares estimates of the parameters β0, β1, and β2 in the model:

 

η = β0 + β1X1 + β2X2

 

where η = the mean value of Y.

 

(b)Which variable influences tool life more over the region of experimentation, feed or speed?

(c)Obtain a 95% confidence interval for β2, assuming that the standard deviation of the observations σ = 2.

(d)Carry out any further analysis that you think is appropriate.

(e)Is there a simpler model that will adequately fit the data?

 

2.Using the data below, determine the least square estimates of the coefficients of this model:

 

η = β0 + β1X1 + β2X2 + β3X3

 

 

where η is the mean value of the drying rate.

 

 

Temperature

(deg C)

Feed rate

(kg/min)

Humidity

(%)

Drying rate

(coded units)

300

15

40

3.2

400

15

40

5.7

300

20

40

3.8

400

20

40

5.9

300

15

50

3.0

400

15

50

5.4

300

20

50

3.3

400

20

50

5.5

Coding for the variables is as follows:

 

 

Xi

i = 1

temperature

(deg C)

i = 2

feed rate

(kg/min)

i = 3

humidity

(%)

-1

300

15

40

+1

400

20

50

 

The coding equation for temperature is

 

X1 = 1/50 ( temperature in units of deg.C - 350 deg.C)

 

 

  1. What are the coding equations for feed rate and humidity?
  2. The design is a 23 factorial. What are the relations between the estimates of β0, β1, β2, β3 and the factorial effects calculated in the usual way?

 

 

 

3.Mr. A and Mr. B, both newly employed, pack crates of material. Let X1 and X2 be indicator variables showing which parker is on duty, and Y be the number of crates packed. On 9 successive working days these data were collected:

 

Day

t

A

X1t

B

X2t

 

Yt

1

1

0

48

2

1

1

51

3

1

0

39

4

0

1

24

5

0

1

24

6

1

1

27

7

0

1

12

8

1

0

27

9

1

1

24

 

Denote by β1 and β2 the number of crates packed per day by A and B, respectively.

First entertain the model

 

η = β1X1 + β2X2

 

Carefully stating what assumptions you make, do the following:

  1. Obtain least squares estimates of β1 and β2 .
  2. Compute the residuals {Ytt}.
  3. Calculate Σt X1t (Ytt) and Σt X2t (Ytt) , where t runs from 1 to 9.
  4. Show an analysis of variance appropriate for contemplation of the hypothesis that A and B pack at a rate of 30 crates per day, the rate laid down by the packers’ union.
  5. Split the residual sum of squares into a lack-of-fit term, SL = Σu 3(Ŷu - Ϋu)2 and an “error” term Σu Σi (Yui-Ϋu)2 ,where u and i run from 1 to 3.(Note: The above design consists of three distinct sets of conditions, (X1, X2) = (0,1), (1,0), (1,1), which are designated by the subscripts u = 1, 2, 3, respectively. The subscripts i = 1, 2, 3 are used to designate the three individual observations included in each set.)
  6. Make a table of the following quantities, each having 9 values:

X1, X2, Yui, Ŷu, Ϋu, Ŷu Ϋu, and Yui-Ϋu, and make relevant plots.

Look for a time trend in the residuals.

  1. at this point it was suggested that the presence of B might stimulate A to do

more (or less) work by an amount β12, while the presence of A might stimulate B to do more (or less) work by an amount β21. Furthemore, there might be a time trend. A new model was therefore tentatively entertained:

 

η = ( β1 + β12X2 ) * X1 + ( β2 + β21X1 ) * X2 + β4 * t

that is,

η = β1X1+ β2X2 + ( β12+ β21 )* X1 * X2 + β4 * t

The β12 and β21 terms cannot be separately estimates, but the combined effect

β12+ β21 = β3 can be estimated from this model:

 

η = β1 * X1+ β2 * X2 + β3 * X3 + β4 * t

where X1*X2 = X3. Fit this model, examine the residuals, and, if the model appears adequate, report least squares estimates of the parameters together with their standard errors.

  1. What do you think is going on? Consider other ways in which the original model could have been wrong.